[LeetoCode]#1450. Number of Students Doing Homework at a Given Time

Environment: Python 3.7

Key technique: zip

Given two integer arrays startTime and endTime and given an integer queryTime.

The ith student started doing their homework at the time startTime[i] and finished it at time endTime[i].

Return the number of students doing their homework at time queryTime. More formally, return the number of students where queryTime lays in the interval [startTime[i], endTime[i]] inclusive.

Example 1:

Input: startTime = [1,2,3], endTime = [3,2,7], queryTime = 4
Output: 1
Explanation: We have 3 students where:
The first student started doing homework at time 1 and finished at time 3 and wasn't doing anything at time 4.
The second student started doing homework at time 2 and finished at time 2 and also wasn't doing anything at time 4.
The third student started doing homework at time 3 and finished at time 7 and was the only student doing homework at time 4.

Analysis:

1. Use zip to get output [(1,3),(2,2),(3,7)]
2. Check q is in those interval.
3. If is yes, it is O.
4. Summarize all O.

Solution:

class Solution:
    def busyStudent(self, startTime, endTime, queryTime):
        ans=0
        m=zip(startTime, endTime)
        for s, e in m:
            if s<=queryTime<=e:
                ans+=1
        return ans

Submissions:

Reference:

Python, straight forward - LeetCode Discuss

http://puremonkey2010.blogspot.com/2015/10/python-python-zip.html