[LeetCode]#893. Groups of Special-Equivalent Strings
Environment: Python 3.8
Key technique: set
You are given an array A
of strings.
A move onto S
consists of swapping any two even indexed characters of S
, or any two odd indexed characters of S
.
Two strings S
and T
are special-equivalent if after any number of moves onto S
, S == T
.
For example, S = "zzxy"
and T = "xyzz"
are special-equivalent because we may make the moves "zzxy" -> "xzzy" -> "xyzz"
that swap S[0]
and S[2]
, then S[1]
and S[3]
.
Now, a group of special-equivalent strings from A
is a non-empty subset of A such that:
- Every pair of strings in the group are special equivalent, and;
- The group is the largest size possible (ie., there isn’t a string S not in the group such that S is special equivalent to every string in the group)
Return the number of groups of special-equivalent strings from A
.
Example 1:
Input: ["abcd","cdab","cbad","xyzz","zzxy","zzyx"]
Output: 3
Explanation:
One group is ["abcd", "cdab", "cbad"], since they are all pairwise special equivalent, and none of the other strings are all pairwise special equivalent to these.The other two groups are ["xyzz", "zzxy"] and ["zzyx"]. Note that in particular, "zzxy" is not special equivalent to "zzyx".
Example 2:
Input: ["abc","acb","bac","bca","cab","cba"]
Output: 3
Analysis:
- Move abcd as two pair ac + bd.
- Sort it and is acbd.
- Check other A[i] is match or not.
- Return all result numbers.
Solution:
class Solution():
def numSpecialEquivGroups(self, A):ans = set()
for a in A:
ans.add(''.join(sorted(a[0::2])) + ''.join(sorted(a[1::2])))
return len(ans)
Submissions:
Reference: