[LeetCode]#441. Arranging Coins

Environment: Python 3.7

Key technique: For, if

Example 1:

n = 5The coins can form the following rows:
¤
¤ ¤
¤ ¤
Because the 3rd row is incomplete, we return 2.

Example 2:

n = 8The coins can form the following rows:
¤
¤ ¤
¤ ¤ ¤
¤ ¤
Because the 4th row is incomplete, we return 3.

Solution:

class Solution:
def arrangeCoins(self, n: int) -> int:
half=n/2
if n==1:
return n
else:
for i in range(1,(int(half)+2)):
if n<i:
return i-1
break
elif n==i:
return i
else:
n=n-i

Submitted result:

Lesson learn:

I don’t consider 1, and remainder is zero case. I spend more time to fix it.

Interesting in any computer science.