# [LeetCode]#2315. Count Asterisks

Environment: Python 3.8

Key technique: split

You are given a string `s`, where every two consecutive vertical bars `'|'` are grouped into a pair. In other words, the 1st and 2nd `'|'` make a pair, the 3rd and 4th `'|'` make a pair, and so forth.

Return the number of `'*'` in `s`, excluding the `'*'` between each pair of `'|'`.

Note that each `'|'` will belong to exactly one pair.

Example 1:

`Input: s = "l|*e*et|c**o|*de|"Output: 2Explanation: The considered characters are underlined: "l|*e*et|c**o|*de|".The characters between the first and second '|' are excluded from the answer.Also, the characters between the third and fourth '|' are excluded from the answer.There are 2 asterisks considered. Therefore, we return 2.`

Analysis:

1. split ‘|’ from input.
2. s= [‘l’, ‘*e*et’, ‘c**o’, ‘*de’, ‘’]
3. check 0, 2, 4, 6….string and count ‘*’ number.

Solution:

`class Solution:   def countAsterisks(self, s: str) -> int:        words = s.split('|')        ans = 0        for i in range(0, len(words), 2):            for j in words[i]:                if j  == '*':                    ans += 1        return ans`

Submissions:

Reference:

https://leetcode.com/problems/count-asterisks/discuss/2545886/Python-Solution