[LeetCode]#2315. Count Asterisks

Environment: Python 3.8

Key technique: split

You are given a string s, where every two consecutive vertical bars '|' are grouped into a pair. In other words, the 1st and 2nd '|' make a pair, the 3rd and 4th '|' make a pair, and so forth.

Return the number of '*' in s, excluding the '*' between each pair of '|'.

Note that each '|' will belong to exactly one pair.

Example 1:

Input: s = "l|*e*et|c**o|*de|"
Output: 2
Explanation: The considered characters are underlined: "l|*e*et|c**o|*de|".
The characters between the first and second '|' are excluded from the answer.
Also, the characters between the third and fourth '|' are excluded from the answer.
There are 2 asterisks considered. Therefore, we return 2.

Analysis:

1. split ‘|’ from input.
2. s= [‘l’, ‘*e*et’, ‘c**o’, ‘*de’, ‘’]
3. check 0, 2, 4, 6….string and count ‘*’ number.

Solution:

class Solution:
   def countAsterisks(self, s: str) -> int:
        words = s.split('|')
        ans = 0
        for i in range(0, len(words), 2):
            for j in words[i]:
                if j  == '*':
                    ans += 1
        return ans

Submissions:

Reference:

https://leetcode.com/problems/count-asterisks/discuss/2545886/Python-Solution