[LeetCode]#2089. Find Target Indices After Sorting Array
Nov 29, 2021
Environment: Python 3.8
Key technique: sort, for
You are given a 0-indexed integer array nums
and a target element target
.
A target index is an index i
such that nums[i] == target
.
Return a list of the target indices of nums
after sorting nums
in non-decreasing order. If there are no target indices, return an empty list. The returned list must be sorted in increasing order.
Example 1:
Input: nums = [1,2,5,2,3], target = 2
Output: [1,2]
Explanation: After sorting, nums is [1,2,2,3,5].
The indices where nums[i] == 2 are 1 and 2.
Analysis:
- Sort it.
- find the target in sorted nums.
- return its index.
Solution:
class Solution:
def targetIndices(self, nums, target):
nums.sort()
ans=[]
for i in range(len(nums)):
if nums[i]==target:
ans.append(i)
return ans
Submissions: