[LeetCode]#1694. Reformat Phone Number

  • 2 digits: A single block of length 2.
  • 3 digits: A single block of length 3.
  • 4 digits: Two blocks of length 2 each.
Input: number = "1-23-45 6"
Output: "123-456"
Explanation: The digits are "123456".
Step 1: There are more than 4 digits, so group the next 3 digits. The 1st block is "123".
Step 2: There are 3 digits remaining, so put them in a single block of length 3. The 2nd block is "456".
Joining the blocks gives "123-456".
Input: number = "123 4-567"
Output: "123-45-67"
Explanation: The digits are "1234567".
Step 1: There are more than 4 digits, so group the next 3 digits. The 1st block is "123".
Step 2: There are 4 digits left, so split them into two blocks of length 2. The blocks are "45" and "67".
Joining the blocks gives "123-45-67".
Input: number = "123 4-5678"
Output: "123-456-78"
Explanation: The digits are "12345678".
Step 1: The 1st block is "123".
Step 2: The 2nd block is "456".
Step 3: There are 2 digits left, so put them in a single block of length 2. The 3rd block is "78".
Joining the blocks gives "123-456-78".
Input: number = "12"
Output: "12
  1. number=”123 4–5678"
  2. replace “-” with “”
  3. replace “ “ with “”
  4. if n size >3, 123-. left number is 45678
  5. if n size >3, 123–456-. Left number is 78
  6. Return 123–456–78
class Solution:
def reformatNumber(self, number):
n = "".join(number.split("-"))
n="".join(n.split(" "))
ans = ''
while len(n) > 4:
ans += n[:3] + '-'
n = n[3:]
if len(n) == 4:
ans += n[:2] + '-' + n[2:]
else:
ans += n
return ans

--

--

Get the Medium app

A button that says 'Download on the App Store', and if clicked it will lead you to the iOS App store
A button that says 'Get it on, Google Play', and if clicked it will lead you to the Google Play store
Fatboy Slim

Fatboy Slim

Interesting in any computer science.