[LeetCode]#1486. XOR Operation in an Array

Environment: Python 3.7

Key technique: ^

Given an integer n and an integer start.

Define an array nums where nums[i] = start + 2*i (0-indexed) and n == nums.length.

Return the bitwise XOR of all elements of nums.

Example 1:

Input: n = 5, start = 0
Output: 8
Explanation: Array nums is equal to [0, 2, 4, 6, 8] where (0 ^ 2 ^ 4 ^ 6 ^ 8) = 8.
Where "^" corresponds to bitwise XOR operator.

Analysis:

1. num=[0,2,4,6,8]
2. Use XOR logic and answer is 8.

Solution:

class Solution:
    def xorOperation(self, n, start):
        ans=0
        for i in range(n):
            ans^=(start+i*2)
        
        return ans

Submissions:

Reference:

https://blog.csdn.net/qq_39378221/article/details/106991130