[LeetCode]#1480. Running Sum of 1d Array

Environment: Python 3.7

Key technique: for, append

Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).

Return the running sum of nums.

Example 1:

Input: nums = [1,2,3,4]
Output: [1,3,6,10]
Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].

Analysis:

1. give tmp=0
2. Use for loop and tmp=tmp+i
3. Use ans to add tmp for each for loop iteration.

Solution:

class Solution:
    def runningSum(self, nums):
        ans=[]
        tmp=0
        for i in nums:
            tmp+=i
            ans.append(tmp)
        return ans

Submissions: