[LeetCode]#1385. Find the Distance Value Between Two Arrays

Input: arr1 = [4,5,8], arr2 = [10,9,1,8], d = 2
Output: 2
Explanation:
For arr1[0]=4 we have:
|4-10|=6 > d=2
|4-9|=5 > d=2
|4-1|=3 > d=2
|4-8|=4 > d=2
For arr1[1]=5 we have:
|5-10|=5 > d=2
|5-9|=4 > d=2
|5-1|=4 > d=2
|5-8|=3 > d=2
For arr1[2]=8 we have:
|8-10|=2 <= d=2
|8-9|=1 <= d=2
|8-1|=7 > d=2
|8-8|=0 <= d=2
  1. get list length (arr1) as ans.
  2. If abs(arr1-arr2) <=d, and-=1
  3. Return ans
class Solution:
def findTheDistanceValue(self, arr1, arr2, d):
ans=len(arr1)
for i in arr1:
for j in arr2:
if abs(i-j) <=d:
ans-=1
break
return ans

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Fatboy Slim

Fatboy Slim

Interesting in any computer science.