# [LeetCode]1374. Generate a String With Characters That Have Odd Counts

2 min readApr 26, 2020

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Environment: Python 3.7

Key technique: append.

Given an integer `n`, return a string with `n` characters such that each character in such string occurs an odd number of times.

The returned string must contain only lowercase English letters. If there are multiples valid strings, return any of them.

Example 1:

`Input: n = 4Output: "pppz"`

Analysis:

1. If n is even, add “a” to n-1 location and add “b” in last location.
2. if n is odd , add “a” in all location.

Solution:

`class Solution:    def generateTheString(self, n):        ans=[]        if n%2==0:            for i in range(n-1):                ans.append('a')            ans.append('b')        else:            for i in range(n):                ans.append('a')        return ans`

Improved Solution:

`class Solution:    def generateTheString(self, n):        ans=[]        if n%2==0:            ans=['a' for i in range(n-1)]            ans.append('b')        else:            ans=['a' for i in range(n)]        return ans`

Submission:

Improved Submission:

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