[LeetCode]#1025. Divisor Game
1 min readFeb 8, 2021
Environment: Python 3.8
Key technique: %
Alice and Bob take turns playing a game, with Alice starting first.
Initially, there is a number N
on the chalkboard. On each player's turn, that player makes a move consisting of:
- Choosing any
x
with0 < x < N
andN % x == 0
. - Replacing the number
N
on the chalkboard withN - x
.
Also, if a player cannot make a move, they lose the game.
Return True
if and only if Alice wins the game, assuming both players play optimally.
Example 1:
Input: 2
Output: true
Explanation: Alice chooses 1, and Bob has no more moves.
Example 2:
Input: 3
Output: false
Explanation: Alice chooses 1, Bob chooses 1, and Alice has no more moves.
Analysis:
- If input % 2 =0, return True.
- If input %2 !=0, return False.
Solution:
class Solution:
def divisorGame(self, N: int) -> bool:
return N%2==0
Submissions: